Яндекс.Метрика

Wednesday, November 11, 2026

A Knot Unlocks Infinitely Many Ramanujan-Style Equations

 

In 1912, Srinivasa Ramanujan mailed pages of unproven formulas to mathematicians in England. Two of them, now called the Rogers-Ramanujan identities, say that two very different ways of counting partitions always give the same answer.

Try it with 6. Using parts that differ by at least 2, you get 1+5, 2+4 and 6: three ways. Using only parts ending in 1, 4, 6 or 9, you get 1+1+1+1+1+1, 1+1+4 and 6: also three. The identities say the two counts match for every number.

Yifeng Huang, now a postdoc at Emory University, noticed that counting matrices on the pinched curve y² = x³ reproduced one side of these identities. With Ruofan Jiang and Alexei Oblomkov, he linked the identities to a trefoil knot and conjectured infinitely many new families, one for each curve x^a = y^b. Huang, Ken Ono and Kenny Lau proved the conjecture in September 2026, helped by the AI system AxiomProver.

Source: Scientific American, October 29, 2026 — https://www.scientificamerican.com/article/mathematicians-find-an-infinite-number-of-ramanujan-equations/

Wednesday, April 10, 2024

Determine the Equation of a Line that Passes through a Given Point and is Parallel to another Line Described by another Equation

 Write an equation passing through a given point (-2,-2) parallel to the line given by the equation: y=-1/5 x+9 Solution

To find the equation of a line parallel to a given line, we first need to identify the slope of the given line. The equation of the given line is:

�=−15�+9

The slope of this line is −15. Since parallel lines have the same slope, the slope of the line we are trying to find will also be −15.

Next, we use the point-slope form of a line to find the equation of our line. The point-slope form is:

�−�1=�(�−�1)

where (�1,�1) is a point on the line and � is the slope. Plugging in the given point (−2,−2) and the slope −15, we get:

�−(−2)=−15(�−(−2)) �+2=−15(�+2) �+2=−15�−25

Finally, we can rearrange this equation to get it in the standard form:

�=−15�−25−2 �=−15�−125

So, the equation of the line passing through the point (−2,−2) and parallel to the line �=−15�+9 is:

�=−15�−125